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WHO ARE WE?

InstaTutors is a platform created by students to help middle and high school students schedule online tutoring sessions with qualified student tutors. All tutoring sessions are held over video chat, and the service is offered for FREE.

Our mission is to provide better tutoring solutions to students from any background, anywhere.

24

Tutors

137

Students

75

Sessions

What People Say About Us

Get Started

  • Create an account, and verify your email (or login with a Google Account). You will be prompted to enter some basic information about yourself.

    • Request a Tutoring Session

  • Once you're logged in, you can make a tutoring request. Browse all our available courses/subjects here, and use the "view tutors" feature to match with the perfect tutor.
  • You will receive an email when a tutor accepts your request, and your tutor will personally email you shortly after with a link to a private video chat room on appear.in. Simply join when it comes time for your FREE tutoring session!

    • Ask a Question

  • Ask a question in a subject you need help with with our question feature.
  • You will receive a response from a qualified tutor in less than 2 hours, guaranteed! You can check out the answer in the "my questions" section, or your email inbox.

    • 0-1000 points

  • Request sessions at least 1 day in advance, 5 active sessions at a time

    • 1000-2500 points

  • Request sessions at least 1 day in advance, 8 active sessions at a time

    • 2500+ points

  • $25 gift card!
  • Book SAME DAY sessions, 10 active sessions at a time

    • Awards & Achievements

  • You can earn points by attending tutoring sessions and inviting friends to use InstaTutors!
  • Receive privileges by earning more points, and compare yourself to other students on the leaderboard!
  • If you become a Gold-level student, you will receive a $25 gift card of your choice!

    • 0-1000 points

  • Privileges: Request sessions at least 2 days in advance, 5 active sessions at a time

    • 1000-2500 points

  • Privileges: Request sessions at least 1 day in advance, 8 active sessions at a time

    • 2500+ points

  • $25 gift card!
  • Privileges: Book SAME DAY sessions, 10 active sessions at a time
    • Let's Go

    FEATURED QUESTIONS OF THE MONTH

    • Student: How can I solve this Calculus problem?
      lim x → -2 (-) of (x2 -4x+4)/[√(x2-4x-12)]
      Tutor: You want to evaluate the numerator and the denominator separately. The numerator, when you plug in (-2), evaluates to 16. For the denominator, plug in something close to (-2) from the - side, like -2.01. This will give you a small positive within the √. Thus, with 16/(0 +), you get your answer of +∞.
    • Student: Analysis of a gaseous mixture of NO and N2O shows that it contains 52% by weight of nitrogen. What is the percent by weight of NO in the mixture?
      Tutor: To solve this, you want to find the percent of N in each compound of the mixture: N2O and NO - once you find these decimals you set up an equation that’s multiplying each compounds % N times percent of the compound (NO and N2O) NO in this case would be x and N2O would be (1-x)
    • Student: I need help with this:
      Find lim x → ∞ of tan-1 [(x3+4x2+1)/√(4x4+7)]
      Tutor: Simplify it so that you have tan-1 [(x3 /2x2)].
      You can get rid of the the 4x2 + 1 and the 7 because they become insignificant once x reaches a large value.
      From tan-1[(x3/2x2)], you find that the value inside tan-1 approaches ∞, so the entire expression approaches π/2.

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